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20n^2-38n-30=0
a = 20; b = -38; c = -30;
Δ = b2-4ac
Δ = -382-4·20·(-30)
Δ = 3844
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$n_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$n_{2}=\frac{-b+\sqrt{\Delta}}{2a}$$\sqrt{\Delta}=\sqrt{3844}=62$$n_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-38)-62}{2*20}=\frac{-24}{40} =-3/5 $$n_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-38)+62}{2*20}=\frac{100}{40} =2+1/2 $
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